Answer to Question #326224 in General Chemistry for bebot

Question

in a gas mixture composed of N2, Ne, and He, the partial pressure of N2 is 0.60 atm, Ne is 1.5 atm, and He is 0.90 atm. What is the total pressure of the mixture?.Calculate the mole fraction of each gas

Answer 1

P_tot = P_N2 + P_Ne + P_He = 0.60 atm + 1.5 atm + 0.90 atm = 3.0 atm

$\chi$_N2 = P_N2 / P_tot = 0.60 atm / 3.0 atm = 0.2

$\chi$_Ne = P_Ne / P_tot = 1.5 atm / 3.0 atm = 0.5

$\chi$_He = P_He / P_tot = 0.9 atm / 3.0 atm = 0.3