Answer to Question #326148 in General Chemistry for niyah

Question

how much heat energy is used to vaporize 3.5 mol of chloroethane at its normal boiling point 12.3°c given Hvap= 24.7k/mol

Answer 1

n(chloroethane) = 3.5 mol;

T_b = 12.3 C = 285.3 K;

H_vap = 24.7 kJ/mol;

H_vap = Q/n

Q = H_vap * n = 24.7 * 3.5 = 86.45 kJ.

Answer: 86.45 kJ.