How much heat is absorbed by 20 g granite boulder as energy from the sun causes its temperature to change from 10°C to 29°C? (Specific heat capacity of granite is 0.1cal/goC) 38 cal
Solve for the heat absorbed
Q = m×c×∆T×Q = (20 g)(0.1 cal/g°C)(29 °C - 10 °C) = 38 cal
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