Answer to Question #318117 in General Chemistry for shav

Question

Calculate the amount of water (in grams) that must be added to 15.0 g of sucrose (C12H22O11) to make a solution with a concentration of 7.50 mass %.

Answer 1

Answer=35g

Explanation:

So, a

7.50

%

by mass urea solution will contain

7.50 g

of urea, the solute, for every

100 g

of the solution. This means that the mass of the solution that contains

15.0 g

of urea will be equal to

15.0

g urea

⋅

= 7.50% by mass urea



100 g solution

7.50

g urea

=50g solution

Since you know that

mass of solution



50 g

=

mass of solute



50 g

+

mass of solvent

you can say that this solution will require

mass of solvent

=

50 g

−

15 g

mass of solvent = 35 g

of water, your solvent.