DETERMINE THE MOLARITY OF A SOLUTION CONTAINING 2.40 G OF SODIUM CHLORIDE IN 40.0 ML OF SOLUTION.
M(NaCl)=23+35.5=58.5 g/mol
n(NaCl)=2.4 /58.5=0.04 mol
40 ml=0.04 l
c(NaCl)=0. 04/0.04=1 mol/l
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