Answer to Question #318042 in General Chemistry for arvi

Question

CALCULATE THE MOLE FRACTION OF EACH COMPONENT OF A SOLUTION CONTAINING 65 G OF ETHANOL IN 350 G OF WATER.

Answer 1

χ_i = n_i / Σn_i

n_i - moles of component

Σn_i - total mole of solution

n(C₂H₅OH) = m(C₂H₅OH)/Mr(C₂H₅OH)

n(C₂H₅OH) = 65 g / 46 g/mole= 1.41 mole

n(H₂O) = m(H₂O)/Mr(H₂O)

n(H₂O) = 350 g / 18g/mole = 19.44 mole

Σn_i = n(C₂H₅OH) + n(H₂O)

Σn_i = 1.41 mole + 19.44 mole = 20.85 mole

χ(C₂H₅OH) = n(C₂H₅OH) / Σn_i = 1.41 mole / 20.85 mole = 0.068

χ(H₂O) = n(H₂O) / Σn_i = 19.44 mole / 20.85 mole = 0.932