2.) Calculate ΔG⁰ for a reaction where ΔH⁰ is equal to 36.2 kJ and ΔS⁰ is equal to 123 J/K at 298 K. Is this a spontaneous reaction?
ΔG⁰ = ΔH⁰ – TΔS⁰
ΔG⁰ = 36.2 kJ – (298 K x 123 J/K)
ΔG⁰ = -0.4 kJ
Therefore the reaction is spontaneous because ΔG⁰ is negative
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