If 40.0dmcube of nitrogen is collected over water of 22 °c when atmospheric pressure Is 727 Torr,what is the volume of dry nitrogen at standard temperature and pressure, assuming ideal behavior?
We use the equation: P1V1/T1 = P2V2/T2
Convert the units:
T = 220C = 295.15 K – initial temperature
At STP P = 760 Torr
At 220C vapor pressure of water is 19.5 Torr
We subtract it from general pressure:
760 – 19.5 = 740.5 Torr
T = 298 K – standard temperature
727*40.0/295 = 740.5*V2/298
98.58 = 2.48 V2
V2 = 39.75 dm3
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