The volume of a given mass ofgas is 300cm cube of 27degree celcius and 700mmHg. What will be it volume of 36degree celcius and 750mmHg
Temperatures in Kelvins:
27oC = 273 + 27 = 300 K
36oC = 273 + 36 = 309 K
According to the combined gas law,
P1V1T1=P2V2T2\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}T1P1V1=T2P2V2
Therefore,
V2=P1V1T2T1P2=700 mmHg×300 cm3×309 K300 K×750 mmHg=288 cm3V_2=\frac{P_1V_1T_2}{T_1P_2}=\frac{700\ mmHg\times300\ cm^3\times309\ K}{300\ K\times750\ mmHg}=288\ cm^3V2=T1P2P1V1T2=300 K×750 mmHg700 mmHg×300 cm3×309 K=288 cm3
Answer: 288 cm3
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