Answer to Question #305092 in General Chemistry for shane

Question

How much energy is required to change 2600 gram of ice at 0˚C into water at the same temperature?

Answer 1

So firstly you need to convert ice (solid state) to water (liquid state), for which you need to supply Latent Heat of Fusion for ice.

The Latent Heat of Fusion for ice is 384J/gram.

So 10 grams of ice require:

10X384 = 3840J of energy.

Next we need to raise the temperature of this water from 0°C to 20°C.

The specific heat capacity of water is:

4.184J/g/°C.

So 10g water from 0°C to 20°C require:

10X20X4.184 = 836.8J

Total energy required

= 3840 + 836.9

= 4676.9J