What is the volume of a sample of ethane at 467k and 1.1atm ,if it occupies 405ml at 298k and 1.1atm
In the question given that,
P1= 1.1 atm, T1= 467 K, V1=?
P2= 1.1 atm , T2= 298 K, V2 = 405 ml
P1V1T1=P2V2T2\frac{P_1V_1}{T_1}= \frac{P_2V_2}{T_2}T1P1V1=T2P2V2
1.1V1467=1.1×405298\frac{1.1V_1}{467}= \frac{1.1×405}{298}4671.1V1=2981.1×405
V1=634.67V_1= 634.67V1=634.67 ml
So, volume of sample is 634.67 ml
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