Answer to Question #303900 in General Chemistry for Eli

Question

 Calculate the standard heat of reaction for the following reaction. Express your answer in kcal/mol.

ΔH° CH₃ OH(l) = -57.0 kcal/mol

ΔH° CO₂ (g) = -94.1 kcal/mol

ΔH° H₂O(l) = -68.3 kcal/mol

2 CH₃OH(l) + 3 O₂(g) → 2 CO₂(g) + 4 H₂O(l)

Answer 1

Standard heat of reaction is calculated by summing the standard heat of formation of the reactants and subtracting the value from the sum of the standard heat of formation of the products.

Standard heat for oxygen is 0kcal/mol

From the balanced equation;

Standard heat of products=

2(-94.1)+(4)(-68.3) = -461.4

Standard heat of reactants=

2(-57.0) + 3(0) = -114

Therefore standard heat of reaction;

= (-461.4) - (-114)

= -347.4 kcal/mol