Question

a.      Calculate the pH of a solution consisting of 1.35M acetic acid (CH₃COOH)

 (pKa= 1.8 x 10^-5) and 2.83 M sodium acetate (NaC₂H₃O₂).

Answer 1

pH= pKa + log([base]÷[acid])

=-log(1.8×10^-5 ) + log (2.83÷1.35)

= 4.74+0.321

= 5.06