Question #299496

A piece of aluminum with a mass of 30 grams was heated in a steam jacket to 98 oC and then plunged into 120 grams of water at 9 oC, causing the temperature to rise to 13.5 oC. What is the specific heat of aluminum


Expert's answer

Let specific heat capacity of water =4.184J/g/K=4.184J/g/K


Heat lost =30×c(9813.5)=30×c(98-13.5)

=2583c=2583c


Heat gained =120×4.184(13.59)=120×4.184(13.5-9)

=2259.36=2259.36


2583c=2259.362583c=2259.36

c=0.8747J/g/Kc=0.8747J/g/K



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