Answer to Question #299492 in General Chemistry for ellise

Question

In an experiment designed to measure the heat of fusion of ice, 25 grams of ice at 0

oC is

dropped into 200 grams of water at 30

oC contained in a copper calorimeter of mass 100 g. The

final temperature is 17.5

oC. What value of the heat of fusion do this value yield? Specific

heat of copper = 0.0931 cal/gC

o

. (10

Answer 1

Let, mass of water used =m Since, Heat gained = Heat lostm1​cΔt1​=mL+m2​cΔt2​m×4.2×(60−10)=(40×336)+(40×4.2×(10−0))m×4.2×50=(40×336)+1680Therefore, the mass of water used, m=42×5
13440+1680​=210
15120​=72g