Answer to Question #299323 in General Chemistry for Madey

Question

Determine the ratio of the electric force to the gravitational force between an electron and a proton when separated by a distance r.

Answer 1

Mass of electron, m_e$=9.11×10^{-31}kg$

Mass of proton$m_p= 1.67×10^{-27}kg$

Newton Gravitational constant$G= 6.67×10^{-11}Nm^2kg^{-2}$

Gravitational force $F_G=$

$=\frac{GM_pM_e}{r^2}=(6.67×10^{-11})\>\>\frac{1.67×10^{-27}×9.1×10^{-31}}{r^2}$

$=\frac{1.015×10^{-67}}{r^2}$

Electric force $F_e=\frac{Kq_eq_e}{r^2}=\frac{9×10^9×(1.6×10^{-19})^2}{r^2}$

$=\frac{2.304×10^{-28}}{r^2}$

$\frac{F_e}{F_q}=2.27×10^{39}$