An ice cube of mass 65 g is taken from a freezer at -15
oC and dropped into 125 cm3 of water at
85
oC. What will be the final temperature of the mixture? The specific heat of ice is 0.5 cal/g.oC
and latent heat of fusion of ice is 80 cal/g.
Initial temperature, T1= -15°c
"Q= m\u00d7 c\u00d7 dT"
80= 190× 0.5× ( T2-T1)
80= 190× 0.5( T2+15)
80= 190× 0.5T2+ 7.5
0.421= 0.5T2+ 7.5
7.921= 0.5T2
T2= 15.8°c
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