Question

how to calculate the volume of nitrogen gas needed to produce 104.6g of ammonia from N2+H3 =2NH3

Answer 1

$N_2+3H_2\to 2NH_3$

Molar mass of ammonia$= 17g/mol$

Moles of $NH_3=6.153\>moles$

Moles of $N_2= \frac{1}2× 6.153=3.076\>moles$

Molar gas volume at r.t.p.= 24.0dm³

Volume of $N_2 = 24×3.076$

= 73.84dm³