For the balanced equation shown below, how many grams of H2O would be produced by 39.7 grams of Fe3O4? Fe3O4+4H2 → 3Fe+4H2O
Convert the amount of each reactant excess into grams using its molecular weight. Weight is equal to molecular weight multiplied by the number of moles. CaCO3 is the only excess reactant in this example, so the amount of CaCO3 is 100.089 * 0.061 = 6.105 grams.
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