How many grams of Cu would have to react to produce 89.5 grams of Ag?
The balanced chemical equation:
Cu + 2AgNO3= Cu(NO3)2 + 2Ag
According to the equation: n(Cu) = n(AgNO3)/2
Moles of AgNO3 = Mass of AgNO3 / Molar mass of AgNO3
The molar mass of AgNO3 is 169.87 g mol
n(AgNO3) = Moles of AgNO3 = 45.0 g / 169.87 g mol-1 = 0.2649 mol
n(Cu) = n(AgNO3)/2 = 0.2649 mol / 2 = 0.13245 mol
Moles of Cu = Mass of Cu / Molar mass of Cu
The molar mass of Cu is 63.546 g mol-1.
Hence,
Mass of Cu = Moles of Cu × Molar mass of Cu = 0.13245 mol × 63.546 g mol-1 = 8.41667 g = 8.42 g
Mass of Cu is 8.42 grams.
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