Answer to Question #299139 in General Chemistry for hazy

Question

A 120.15 mL intravenous (IV)

solution contains 7.10 g of

glucose (C6H12O6). What is the

molarity of this solution? The molar mass of glucose is 180.16 g/mol.

Answer 1

Solution:

Number of moles = Mass / Molar Mass

Molarity = Number of moles / Liters of solution

Therefore,

Molarity = (Mass) / (Liters of solution × Molar Mass)

Molarity = (7.10 g) / (0.12015 L × 180.16 g/mol) = 0.328 mol/L = 0.328 M

Molarity = 0.328 M

Answer: The molarity of this solution is 0.328 M