Question

How many kilograms of iron are present in 115 kg

kg of hematite?

Answer 1

Molar mass of Hematite $(Fe_2O_3)=159.69$

Molar mass of Iron $=55.845$

Mass of Iron in 1 mole of Hematite$=2×55.845$

$=111.69$

Mass ratio $Fe_2O_3:Fe=159.69:111.69$

In 115kg of $Fe_2O_3$

Mass of Iron $=\frac{111.69}{159.69}×115kg$

$=80.43kg$