Question #297453

At STP a certain mass of gas occupies a volume of 800 cm cube find the temperature at which the gas occupy 900 cm cube and has a pressure of 675mmhg


1
Expert's answer
2022-02-15T00:00:02-0500

Standard Temperature and Pressure (STP) is defined as 0 degrees Celsius and 1 atmosphere of pressure.

T1=0=273  KV1=800  cm3P1=1  atmV2=940  cm3T_1 = 0 = 273 \;K \\ V_1 = 800 \;cm^3 \\ P_1 = 1 \;atm \\ V_2 = 940 \;cm^3

Let’s use the value of P2=1520  mmHg=2  atmP_2 = 1520 \;mmHg = 2 \;atm \\

P1×V1T1=P2×V2T2T2=T1×P2×V2P1×V1=273×2×9401×800=641.55  KT2=368  ºC\frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2} \\ T_2 = \frac{T_1 \times P_2 \times V_2}{P_1 \times V_1} \\ = \frac{273 \times 2 \times 940}{1 \times 800} \\ = 641.55 \;K \\ T_2 = 368 \;ºC

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