What is the percent composition of the element hydrogen in the compound methane, CH4?
The molar mass of CH4 "M=12.011+4\\times1.008=16.043\\frac{g}{mol}"
"\\%H=\\frac{4\\times{A_r(H)}}{M\\ (CH_4)}\\times100\\%=\\frac{4\\times1.008\\ g\/mol}{16.043\\ g\/mol}\\times100\\%=25.13\\%"
Answer: 25.13%
Comments
Leave a comment