The complete combustion of 1 mole of propane (C3H8) is represented by the reaction shown. C3H8 + 5O2 → 3CO2 + 4H2O How many grams of water are produced in this reaction?
From the balanced equation, 4 moles of water was produced in the reaction.
Number of moles = mass/molar mass
Molar mass of water = (1*2)+16
= 18
4 = mass/18
Mass = 4*18
Therefore, the mass of water produced in the reaction is 72g.
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