Question

The complete combustion of 1 mole of propane (C₃H₈) is represented by the reaction shown. C₃H₈ + 5O₂ → 3CO₂ + 4H₂O How many grams of water are produced in this reaction?

Answer 1

From the balanced equation, 4 moles of water was produced in the reaction.

Number of moles = mass/molar mass

Molar mass of water = (1*2)+16

= 18

4 = mass/18

Mass = 4*18

Therefore, the mass of water produced in the reaction is 72g.