Suppose that 181.1 J of heat energy is required to completely vaporize 3.9 g of a pure liquid. If the molar mass of the liquid is 128.34 g/mol, what is the molar enthalpy of vaporization of the liquid?
Moles evaporated"=\\frac{3.9}{128.34}"
Molar enthalpy of evaporation"=\\frac{128.34}{3.9}\u00d7\\frac{181.1}{1000}"
"=5.9596kJ\/mol"
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