72cm³ of a mixture of Nitrogen and Nitrogen oxide were passed over heated copper until all the nitrogen oxide had been reduced to nitrogen. The volume of the resulting gas was 60cm³, calculate the volume of nitrogen oxide in the original mixture.
2NO+2Cu"=" 2CuO+ N2
Let V"=" Volume of Nitrogen
Volume of NO "=72-V"
Volume of "N_2=60-V"
NO:N2 "=2:1"
"72-V=2(60-V)"
"V=48"
Volume of NO "=72-48=24cm^3"
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