Question

72cm³ of a mixture of Nitrogen and Nitrogen oxide were passed over heated copper until all the nitrogen oxide had been reduced to nitrogen. The volume of the resulting gas was 60cm³, calculate the volume of nitrogen oxide in the original mixture.

Answer 1

2NO+2Cu$=$ 2CuO+ N₂

Let V$=$ Volume of Nitrogen

Volume of NO $=72-V$

Volume of $N_2=60-V$

NO:N₂ $=2:1$

$72-V=2(60-V)$

$V=48$

Volume of NO $=72-48=24cm^3$