Question

An actual yield of 18g, the theoretical yield is unknown. Calculate the theoretical yield?

Answer 1

Question is incomplete but,

Actual yield is normally smaller than the theoretical yield

Consider burning 35g of glucose

$C_6H_{12}O_6+6O_2\to6CO_2+6H_2O$

Theoretical yield of water can be calculated as follows:

Moles of $C_6H_{12}O_6=\frac{35}{180}$

Moles of water $=6×\frac{35}{180}$

Mass of water $=6×\frac{35}{180}×18$

$=21g$

If 18g of water was produced, instead of 21g

21g represent the theoretical yield.