An actual yield of 18g, the theoretical yield is unknown. Calculate the theoretical yield?
Question is incomplete but,
Actual yield is normally smaller than the theoretical yield
Consider burning 35g of glucose
"C_6H_{12}O_6+6O_2\\to6CO_2+6H_2O"
Theoretical yield of water can be calculated as follows:
Moles of "C_6H_{12}O_6=\\frac{35}{180}"
Moles of water "=6\u00d7\\frac{35}{180}"
Mass of water "=6\u00d7\\frac{35}{180}\u00d718"
"=21g"
If 18g of water was produced, instead of 21g
21g represent the theoretical yield.
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