how many moles of gas would you have if you had a volume of 50.0 L at a pressure of 1.01 atm?
PV = nRT
T = PV/nR
R is a constant with a value of 0.0821L.atm/mol.K
5.00gH2 (1mol H2/2g H2) = 2.5 mol H2
T = (1.01atm ×50.0L)/ 2.5mol H2× (0.0821.L.atm/mol.k)
= 50.5L.atm/0.20525L.atm/K
= 246K
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