u4) If 46.2 mL of 2.50 M NaOH is required to neutralize 25.00 mL of a phosphoric acid, H_3PO_4, solution, what is the molarity of the phosphoric acid?
3 NaOH + H_3 PO_4→ 〖Na〗_3 PO_4 + 3 H_2 O
Moles of NaOH "=0.0462\u00d72.50=0.1155moles"
Moles is "H_3PO_4=\\frac{0.1155}{3}=0.0385"
Molarity "=\\frac{0.0385}{0.025}=1.54M"
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