Answer to Question #290399 in General Chemistry for Ara

Question

If 7.3 mL of 1.25 M 𝐻𝑁𝑂_3 is required to neutralize 25.00 mL of a potassium hydroxide solution, what is the molarity of the potassium hydroxide?

𝐻𝑁𝑂_3 + KOH →KN𝑂_3 + 𝐻_2 𝑂

Answer 1

Mole ratio of

HNO_{3 ;} KOH$=1:1$

$\frac{7.3}{1000}×1.25=\frac{25}{1000}×M_k$

$M_k=\frac{7.3×1.25}{25}$

$0.365M$