Determine the heat absorbed by 250g of water heated for 20mins and had a temperature increase of 45ⁿC.(Specific heat capacity of water=4.184J/gⁿC)
q=m×Cg× change in temperature
q=heat absorbed
m=mass of water
Cg= specific heat capacity of water
q = (250×4.184×45)J
= 47070 Joules
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