For AI-28, calculate a)the mass defect (use table 18.4) and b) the binding energy in kJ/mol.
Solution
Al-28 =27.981910 amu
Al has 13 protons
28-13=15
15 neutrons
proton=1.00727647 amu
Neutron=1.00866490 amu
predicted mass =13(1.00727647)+15(1.00866490)
=28.22456761 amu
Mass defect= Predicted mass - Actual mass
28.22457-27.98191= 0.24266 amu
b) Binding energy
E=mc2
1 amu = 1.66054 x 10-27kg
c= 2.99792 x108
(0.24266 x 1.66054 x 10-27) x (2.99792 x 108)
= 3.62149 x10-11 J
convert to KJ/mole
"\\frac{3.62149 \\times 10^-11}{6.022 \\times 10^20}"
=6.01377×1032kJ/mol
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