Answer to Question #286929 in General Chemistry for Rookie

Question

The reaction between potassium chlorate and red phosphorus takes place when you strike a match on a matchbox. This happens in the reaction

KClO3 + P4 = P4O10 + KCl

If there are 0.895 g of KClO3 and 0.995 of P4

a. Which is the limiting reactant

b. How much KCl is produced in the reaction?

Answer 1

Molar mass of KClO3=122.55

0.895/122.55=0.0073

Molar mass of P4=123.9

0.995/123.9= 0.008

KCLO3 is the limiting reactant