using standard molar enthalpies of formation given, calculate the standard enthalpy of reaction for the combustion of propane (C3H8) into carbon dioxide and water.
C3H8(g)+5O2(g) = #CO2(g)+ 4H2O(g)
Substance= ΔH°f(kJ/mol)
C3H8(g)= -104.0
O2(g)= 0
CO2(g)= -393.5
H2O(g)= 241.8
Standard enthalpy =−2043.9kJ/mol
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