Answer to Question #285100 in General Chemistry for jatjat

Question

There are 11.7 g of ethane and 30.5 g of oxygen that will undergo combustion

Answer 1

If 4.5 mol of ethane, C₂H₆, undergo combustion according to the unbalanced equation the amount of O₂ is the same that amount of ethane.

C₂H₆ + O₂ ----> CO₂ + H₂O, so it is 4.5 mol of O₂

But when it is balanced equation the amount of O₂ is next,

C₂H₆ + 7/2 O₂ ----> 2CO₂ + 3H₂O

4.5 mol* 7/2 = 15.72 mol