Question #284885


A student prepares a solution of sodium sulfate, Na,SO,, by adding 6.25 x 10-2 mol dm-8


sulfuric acid, H, SO;, from a burette to 25.0 cm° of 0.124 mol dm-3 NaOH in a conical flask.


2NaOH(ag) + HaS0, (aq) -› NaySO,(aq) + 2H, 0()


Calculate the minimum volume of the H,SO, that the student would need to completely react


with the NaOH present.


Expert's answer

2NaOH + H2SO4 --> Na2SO4 + 2H2O

According to the equation,

n(NaOH)=2n(H2SO4)n(NaOH)=2{n(H_2SO_4)}

Therefore,

CNaOHVNaOH=2CH2SO4VH2SO4;C_{NaOH}V_{NaOH}=2C_{H_2SO_4}V_{H_2SO_4};


VH2SO4=CNaOHVNaOH2CH2SO4=25.0 cm3×0.124 M2×0.0625 M=24.8 cm3V_{H_2SO_4}=\frac{C_{NaOH}V_{NaOH}}{2C_{H_2SO_4}}=\frac{25.0\ cm^3\times0.124\ M}{2\times0.0625\ M}=24.8\ cm^3


Answer: 24.8 cm3

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