A student prepares a solution of sodium sulfate, Na,SO,, by adding 6.25 x 10-2 mol dm-8
sulfuric acid, H, SO;, from a burette to 25.0 cm° of 0.124 mol dm-3 NaOH in a conical flask.
2NaOH(ag) + HaS0, (aq) -› NaySO,(aq) + 2H, 0()
Calculate the minimum volume of the H,SO, that the student would need to completely react
with the NaOH present.
2NaOH + H2SO4 --> Na2SO4 + 2H2O
According to the equation,
"n(NaOH)=2{n(H_2SO_4)}"
Therefore,
"C_{NaOH}V_{NaOH}=2C_{H_2SO_4}V_{H_2SO_4};"
"V_{H_2SO_4}=\\frac{C_{NaOH}V_{NaOH}}{2C_{H_2SO_4}}=\\frac{25.0\\ cm^3\\times0.124\\ M}{2\\times0.0625\\ M}=24.8\\ cm^3"
Answer: 24.8 cm3
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