Question

What is the mass in grams of CuO that would be required to produce 86.00 moles of nitrogen gas in the following chemical reaction?

2 NH₃(g) + 3 CuO(s) → 3 Cu(s) + N₂(g) + 3 H₂O(g)

Answer 1

2 NH₃(g) + 3 CuO(s) → 3 Cu(s) + N₂(g) + 3 H₂O(g)

mole ratio: $CuO:N_2=3:1$

moles of $CuO=86\times 3=258moles$

$RMM$ of CuO= 79.545

mass of $CuO=79.545\times 258=20522.61g$