Answer to Question #280524 in General Chemistry for neider

Question

What is the mass in grams of CuO that would be required to produce 86.00 moles of nitrogen gas in the following chemical reaction?

2 NH₃(g) + 3 CuO(s) → 3 Cu(s) + N₂(g) + 3 H₂O(g)

Answer 1

2 NH₃(g) + 3 CuO(s) → 3 Cu(s) + N₂(g) + 3 H₂O(g)

mole ratio: $CuO:N_2=3:1$

moles of $CuO=86\times 3=258moles$

$RMM$ of CuO= 79.545

mass of $CuO=79.545\times 258=20522.61g$