Answer to Question #269001 in General Chemistry for zarra

Question

A substance has a molar enthalpy of combustion of 810.4 kJ/mol. When 0.285 mol of the substance is burned in a calorimeter containing 8.60 kg of water, the increase in the temperature of water is:

Answer 1

$Q= n×c× dT$

Q= 810•4kj/mol

n= 0.285mol

C= 42

dT=810.4/(42×0.285)

= 67.7 ⁰C