Answer to Question #268995 in General Chemistry for chem

Question

The heat required to melt and warm the ice is a two-part process.  First energy will be used to change the phase of the ice from solid to liquid.  This constant used to calculate this amount of energy is what we are trying to determine experimentally, the heat of fusion, Fusion, and will be reported in J/g in this lab.

Answer 1

The temperature of the ice rises linearly, absorbing heat at a constant rate of 0.50 cal/gâ‹…C until it reaches

0 ºC. Once at this temperature, the ice begins to melt until all the entire sample has melted, absorbing a total of 79.8 cal/g of heat. The temperature remains constant at 0 ºC during this phase change. Once all the ice has melted, the temperature of the liquid water rises, absorbing heat at a new constant rate of 1.00 cal/g⋅C (remember that specific heats are dependent on phase). At 100ºC, the water begins to boil and the temperature again remains constant until the water absorbs 539 cal/g of heat to complete this phase change.