Consider the reaction: 3HNO3(aq) + K3PO4(aq) H3PO4 + 3KNO3(aq) What is the concentration of an HNO3 solution if 25.0 mL reacts with 38.5 mL of 0.145 M K3PO4?
Solution:
Balanced chemical equation:
3HNO3(aq) + K3PO4(aq) → H3PO4 + 3KNO3(aq)
According to stoichiometry:
3 mol of HNO3 reacts with 1 mol of K3PO4
Therefore,
Moles of HNO3 = 3 × Moles of K3PO4
Moles = Molarity × Volume
Therefore,
Molarity of HNO3 × Volume of HNO3 = 3 × Molarity of K3PO4 × Volume of K3PO4
Molarity of HNO3 × (25.0 mL) = 3 × (0.145 M) × (38.5 mL)
Molarity of HNO3 = (3 × 0.145 M × 38.5 mL) / (25.0 mL) = 0.6699 M = 0.670 M
Molarity of HNO3 = 0.670 M
Answer: The molar concentration of an HNO3 solution is 0.670 M
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