Answer to Question #266166 in General Chemistry for grizz

Question

How many moles of nitrogen gas would be produced if 7.83 moles of copper(II) oxide were reacted with excess ammonia in the following chemical reaction?

2 NH₃(g) + 3 CuO (s) → 3 Cu(s) + N₂(g) + 3 H₂O(g)

Answer 1

Mole ratio=3:1

Moles of CuO=7.83

Moles of Nitrogen=$\frac{7.83}{3}=2.61 moles$

Moles of $N_2=7.83moles$