Question

How many moles of nitrogen gas would be produced if 7.83 moles of copper(II) oxide were reacted with excess ammonia in the following chemical reaction?

2 NH₃(g) + 3 CuO (s) → 3 Cu(s) + N₂(g) + 3 H₂O(g)

Answer 1

Mole ratio=3:1

Moles of CuO=7.83

Moles of Nitrogen=$\frac{7.83}{3}=2.61 moles$

Moles of $N_2=7.83moles$