Answer to Question #266154 in General Chemistry for Challyking

Question

If 50cm3 of a saturated solution of potassium chloride at 30°C yielded 18.62g of dry salt, calculate the solubility of the salt in mol/dm³ at 30°C

Answer 1

If 18.62g is desolved in 50ml of water,

Then (18.62×2) gram swill be dissolved in (50×2) ml of water at 30°C.

Solubility (grams/100 grams of water)= 37.24g/100g of water

Therefore, 372.4g/1000g of water

Moles=mass/molecular mass

Moles are, 372.4/39=9.5487

Solubility =9.5487moles/litre