Answer to Question #266072 in General Chemistry for Leshelle

Question #266072

If 10.0 g of a solute is added to 100.0 g of water, the mass percent of the solution is



1
Expert's answer
2021-11-15T11:00:07-0500

Mass of solute ++ water


=100+10=100+10

=110g=110g


%m/m=gramofsolutemassofsolution×100%\boxed {\textcolor {blue}{\%m/m=\frac{gram \>of\> solute}{mass\> of\> solution}×100\%}}


10110×100%=9.091%\frac{10}{110}×100\%=9.091\%


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