Answer to Question #266072 in General Chemistry for Leshelle

Question

If 10.0 g of a solute is added to 100.0 g of water, the mass percent of the solution is

Answer 1

Mass of solute $+$ water

$=100+10$

$=110g$

$\boxed {\textcolor {blue}{\%m/m=\frac{gram \>of\> solute}{mass\> of\> solution}×100\%}}$

$\frac{10}{110}×100\%=9.091\%$