If 10.0 g of a solute is added to 100.0 g of water, the mass percent of the solution is
Mass of solute +++ water
=100+10=100+10=100+10
=110g=110g=110g
%m/m=gram of solutemass of solution×100%\boxed {\textcolor {blue}{\%m/m=\frac{gram \>of\> solute}{mass\> of\> solution}×100\%}}%m/m=massofsolutiongramofsolute×100%
10110×100%=9.091%\frac{10}{110}×100\%=9.091\%11010×100%=9.091%
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