Question

How many moles of NO₂ would be required to produce 6.22 moles of HNO₃ in the presence of excess water in the following chemical reaction?

3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)

Answer 1

$3$ moles of $NO_2$ produces $2$ moles of

$2HNO_3$

To produce $6.22$ moles of $HNO_3$ the moles of $NO_2$ will increase in the same ratio

Therefore the numbers of moles of $NO_2=\frac{6.22}{2}×3$

$=9.33$ moles