How many moles of NO₂ would be required to produce 6.22 moles of HNO₃ in the presence of excess water in the following chemical reaction?
3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)
"3" moles of "NO_2" produces "2" moles of
"2HNO_3"
To produce "6.22" moles of "HNO_3" the moles of "NO_2" will increase in the same ratio
Therefore the numbers of moles of "NO_2=\\frac{6.22}{2}\u00d73"
"=9.33" moles
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