Question

50 grams of ice-cold water (0 °C) is heated to boiling (100 °C). The specific heat capacity of water is 4.18 J /g°C. How much energy did the water absorb?

Answer 1

m= 50 g

$Q = mcΔT \\ Q = 50 \times 4.18 \times (100 -0) \\ Q = 20900 \;J = 20.9 \;kJ$