Peroxide reacts with water to produce oxygen. What would be the change in water temperature if we add 7800 grams of sodium peroxide to 110.00 ml of water? Reaction enthalpy = -285.0 kJ. Can you help me understand this problem?
We were given enthalpy
So we have to get our heat quantity first
H=-285000kJ
And ∆H=-Q
Q=285000J
Q=mc∆T
∆T=Q/mc
∆T=285000/(110×4.19)
∆T=618.4°C
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