What is the mass in grams of oxygen gas, O2 is needed to complete the combustion of 6 L of methane, CH4? Assume that the pressure and temperature remain constant. (be sure to write the balanced chemical equation)
CH4 + 2O2 → CO2 + 2H2O
One mole of any gas at STP occupy volume of 22.4 L.
Proportion:
22.4 L – 1 mol
6 L – x
According to the reaction:
n(O2) = 2n(CH4)
M(O2) = 32 g/mol
m(O2)
Answer: 17.14 g
Comments
Leave a comment