Question

Gold has a specific heat of 0.129 J/g· oC. When a 5.00-g piece of gold absorbs 1.33 J of heat, what is the change in temperature? 

Answer 1

Heat absorbed $=$ Mass $×$ specific capacity $×$ Temperature change.

$1.33=5×0.129 ×\Delta\>T$

$\Delta\>T=\frac{1.33}{0.129×5}$

$=2.062°C$