Question

Calculate the mass of carbon dioxide released from the decomposition of 10.0 g of cabalt(|||)carbonate given the unbalanced chemical equation

Answer 1

$2 CO_2(CO_3)_3 ---> 2 CO_2O_3 +3 CO_2$

Molar Mass cabalt(|||)carbonate: 297.8931

Moles $=\frac{10}{297.8931}=0.034moles$

Moles of $CO_2=\frac{3}{2}×0.034=0.051moles$

Mass of $CO_2=44.01×0.051=2.245grams$